Respuesta :

naomi479xx

Hi there!

The general equation of a slope-intercept line looks like this :

y = mx + b

Where "m" is the slope and "b" is the y-intercept.


First you need to isolate the y in your equation in order to have the right slope-intercept form :

6x + 10y = 8

Subtract 6x from each side of the equation

10y = 8 - 6x

Divide each side of the equation by 10

y = 0.8 - [tex]\frac{6x}{10}[/tex]

y = 0.8 - [tex]\frac{3x}{5}[/tex]

y = -[tex]\frac{3}{5}x[/tex] + 0.8


Now that you have your right form of equation, you can easily see that the slope is -[tex]\frac{3}{5}[/tex].


There you go! I really hope this helped, if there's anything just let me know! :)

varshamittal029

The slope of the line 6x+10y=8 is -3/5 unit

What is general equation of line ?

We know that the general equation of line is y=mx+c

where m is the slope of the line.

Example : y = 4x-5, where m = slope = 4

What is the required slope ?

Given equation is 6x+10y=8

We have to convert it into general form of line.

So, 6x+10y=8

⇒ 10y = -6x+8

⇒ y = -6x/10 +8/10

⇒ y = -3x/5+4/5

Comparing it with y = mx+c we get m = -3/5

Learn more about slope here :

https://brainly.com/question/27877215

#SPJ2

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