Answer:
D. 1/16 It's weight on the surface.
Explanation:
As we know that the gravity due to earth at its surface is given as
[tex]g = \frac{GM}{R^2}[/tex]
now at the distance of 4 radius of earth the gravity is given as
[tex]g' = \frac{GM}{(4R)^2}[/tex]
so we can say that
[tex]g' = \frac{g}{16}[/tex]
so here gravity becomes 1/16 times of the gravity due to earth on its surface
now we know that weight on the surface of earth is given as
[tex]W = mg[/tex]
also the weight now at the given height is given by
[tex]W' = mg/16[/tex]
so here correct answer will be
D. 1/16 It's weight on the surface.