Answer:
[tex]5x-5\geq 0[/tex]
Step-by-step explanation:
We are given
[tex]f(x)=\sqrt{5x-5} +1[/tex]
Domain:
we know that domain is all possible values of x for which any function is defined
We know that value inside sqrt should always be positive
so, value inside sqrt is 5x-5
so, we get
[tex]5x-5\geq 0[/tex]