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Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object

Respuesta :

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For 3 kg mass: F = [tex]\lpha ma,a[/tex] = [tex]\frac{F}{m}[/tex] = [tex]\frac{12N}{3kg}[/tex] = 4[tex]\lpha m[/tex] / [tex]s^{2}[/tex]

For 6 kg mass: F = [tex]\lpha ma,a[/tex] = [tex]\frac{F}{m}[/tex] = [tex]\frac{12N}{6kg}[/tex] = 2[tex]\lpha m[/tex] / [tex]s^{2}[/tex]


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