mumpfieldk mumpfieldk
  • 07-11-2018
  • Mathematics
contestada

Solve for x.

25^x=5^x-3

x and x-3 are exponents.

Respuesta :

remotecontrolbrain
remotecontrolbrain remotecontrolbrain
  • 07-11-2018

Answer: [tex]x = -3[/tex]

Step by step:

[tex]25^x=5^{x-3}\\(5^2)^x = 5^{x-3}\\5^{2x}=5^{x-3}\\\log_5 5^{2x}=\log_5 5^{x-3}\\2x\log_5 5=(x-3)\log_5 5\\2x = x-3\\x = -3[/tex]

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