Given:
Voltage of source = 5 V
Charge on capacitor = 10 µC
To find:
Capacitance of the capacitor = ?
Formula used:
Charge on the capacitor is given by,
Q = C V
Where Q = charge
C = capacitance
V = voltage of source
Solution:
Charge on the capacitor is given by,
Q = C V
Where Q = charge
C = capacitance
V = voltage of source
[tex]C = \frac{Q}{V}[/tex]
C =[tex]\frac{10 \times 10^{-6}} {5}[/tex]
C = [tex]2 \times 10^{-6}[/tex] Farad
C = 2 µC
The charge on the capacitor is 2 µC.
