Respuesta :
The exact value of tan(−π) is 0.
We have to determine, the exact value of tan(−π).
The value of tan(−π) is determined by using the trigonometry equation, following all the steps given below.
The value of tan(−π) is,
[tex]tan(\pi ) = \dfrac{sin(\pi )}{cos(\pi )}\\\\[/tex]
The value of sin(π) is 0 and the value of cos(π) = -1,
Substitute the values in the equation,
[tex]tan(\pi ) = \dfrac{sin(\pi )}{cos(\pi )}\\\\tan(\pi ) = \dfrac{0}{-1}\\\\tan(\pi ) = 0[/tex]
The angle in their terminal arm in the quadrant || the value of tangent is negative.
Therefore, The required exact value of tan(−π) is 0.
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