Answer:
The factored form is (y+4)(y+2)
Step-by-step explanation:
We have to factor the expression [tex]y^2+6y+8[/tex]
We can factor it by AC method.
Comparing this equation with [tex]ay^2+by+c[/tex]
a = 1, b = 6, c = 8
Multiply a and c. ac = 8
Factor pairs of 8 are
1, 8
2, 4
Now among these factors pairs we choose the pair which on addition/subtraction given b and on multiplication it gives c.
Hence, require pair is 2 and 4
Thus, we can write the expression as
[tex]y^2+4y+2y+8[/tex]
Take GCF
[tex]y(y+4)+2(y+4)[/tex]
Factor out the common term
[tex](y+4)(y+2)[/tex]
Hence, the factored form is (y+4)(y+2)
