allieballey0727 allieballey0727

07-11-2018
Mathematics

contestada

find the illegal values of b in the fraction.

$find the illegal values of b in the fraction class=$

Respuesta :

KhaRNate KhaRNate

07-11-2018

Denominator can't be zero, so:

b^2 - 2b - 8 = 0
b^2 - 4b + 2b - 8 = 0
b(b-4) + 2(b-4) = 0
(b-4) (b+2) = 0

b-4 = 0
b = 4

b+2 = 0
b = -2

b can't be equal to 4 and -2

Answer: D

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