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Peter processed two catering orders at the sandwich shop where he works. The first order was for 7 trays of club sandwiches and 10 trays of vegetarian sandwiches. That order cost $149. The second order, which cost $10, was for 1 tray of vegetarian sandwiches.
This situation is modeled by the matrix equation shown.
[7   10]  [c]    [149]
[0    1 ]  [v] =  [10]
Determine the cost of a tray of club sandwiches and the cost of a tray of vegetarian sandwiches. SHOW YOUR WORK.





Respuesta :

Answer: Cost of a tray of club sandwiches is $49 and Cost of a tray of vegetarian sandwiches is $70.

Step-by-step explanation:

Since we  have given that

[tex]\begin{bmatrix} 7&10 \\ 0& 1\end{bmatrix}\begin{bmatrix}c \\ v\end{bmatrix}=\begin{bmatrix}149 \\ 10\end{bmatrix}[/tex]

since we know the formula for "System of linear of equation of matrix"

i.e.

[tex]AX=B\\\\Here,\\\\A=\begin{bmatrix} 7&10 \\ 0& 1\end{bmatrix}\\\\X=\begin{bmatrix}c \\ v\end{bmatrix}\\\\B=\begin{bmatrix}149 \\ 10\end{bmatrix}[/tex]

Now, we will solve it :

[tex]\begin{bmatrix}c \\\\ v\end{bmatrix}=\begin{bmatrix} 7&10 \\\\ 0& 1\end{bmatrix}^{-1}\begin{bmatrix}149 \\\\10\end{bmatrix}\\\\\begin{bmatrix}c \\\\ v\end{bmatrix}=\frac{1}{\det \begin{pmatrix}7&10\\ 0&1\end{pmatrix}}\begin{pmatrix}1&-10\\ -0&7\end{pmatrix}\begin{bmatrix}149 \\\\10\end{bmatrix}=\frac{1}{7}\begin{pmatrix}1&-10\\ -0&7\end{pmatrix}\begin{bmatrix}149 \\\\10\end{bmatrix}=\begin{bmatrix} 1&-10 \\\\ 0& 7\end{bmatrix}\begin{bmatrix}149 \\\\10\end{bmatrix}\\\\\begin{bmatrix}c \\\\v\end{bmatrix}=\begin{bmatrix}149-100\\\\70\end{bmatrix}\\\\\begin{bmatrix}c \\\\v\end{bmatrix}=\begin{bmatrix}49\\\\70\end{bmatrix}[/tex]

Hence Cost of a tray of club sandwiches is $49 and Cost of a tray of vegetarian sandwiches is $70.

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