Given coordinates of mall, library, and school on the graph.
Mall (10,6).
Library (-14,6) and
School (10,-4).
Let us find distances from the school to the mall, from the mall to the library and from the school to the library.
The distance from the school to the mall:
[tex]\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]
[tex]=\sqrt{\left(10-10\right)^2+\left(6-\left(-4\right)\right)^2}[/tex]
[tex]=10[/tex]
The distance from the mall to the library :
[tex]=\sqrt{\left(10-\left(-14\right)\right)^2+\left(6-6\right)^2}[/tex]
[tex]=24[/tex]
Distance from the school to the library.
[tex]=\sqrt{\left(10-\left(-14\right)\right)^2+\left(-4-6\right)^2}[/tex]
[tex]=26[/tex]
Britney traveled total = 10+24 = 34 miles.
Alice traveled total = 26 miles.
34-26 = 8 miles.
Therefore, Britney traveled 8 miles more than Alice.
