Find the distance between the points to the nearest tenth.
1. C(-1, -1), D(6, 2)
[tex]\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]
[tex]=\sqrt{\left(6-\left(-1\right)\right)^2+\left(2-\left(-1\right)\right)^2}[/tex]
[tex]=\sqrt{58}[/tex]
= 7.6
2. E(-7, 0), F(5 ,8)
[tex]=\sqrt{\left(5-\left(-7\right)\right)^2+\left(8-0\right)^2}[/tex]
[tex]=4\sqrt{13}[/tex]
=3(3.6)
=10.8
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AB has endpoints A(-3, 2) and B(3, -2).
3. find the coordinates of the midpoint of Line AB
[tex]\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)[/tex]
[tex]=\left(\frac{3-3}{2},\:\frac{-2+2}{2}\right)[/tex]
[tex]=\left(0,\:0\right)[/tex]
4. Find AB to the nearest tenth
[tex]AB = \sqrt{\left(3-\left(-3\right)\right)^2+\left(-2-2\right)^2}[/tex]
[tex]AB =2\sqrt{13}[/tex]
[tex]AB =2(3.6)[/tex]
AB = 7.2 units.
