Answer:
n
Step-by-step explanation:
We are given the following expression of which we have to find the numerator by simplifying it:
[tex](\frac{2n}{6n+4} ).(\frac{3n+2}{3n-2} )[/tex]
To simplify it, factor 2 out of [tex]6n+2[/tex] from the denominator of the first fraction to get:
[tex]\frac{2n}{2(3n+2)} .\frac{3n+2}{3n-2}[/tex]
Cancelling [tex]3n+2[/tex] to get:
[tex]\frac{2n}{2} .\frac{1}{3n-2}[/tex]
Further cancelling 2 to get:
[tex]n.\frac{1}{3n-2}[/tex]
[tex]= \frac{n}{3n-2}[/tex]
Therefore, the numerator of the simplified version of the given expression is n.
