Vera is using her phone. Its battery life is down to \dfrac25
5
2
​ start fraction, 2, divided by, 5, end fraction , and it drains another \dfrac19
9
1
​ start fraction, 1, divided by, 9, end fraction every hour.
How many hours will her battery last?

Respuesta :

We are given that Vera's battery life is down to = [tex]\frac{2}{5}[/tex].

Rate of it drain = [tex]\frac{1}{9}[/tex] per our.

In order to find the number of hours will her battery last, we need to divide [tex]\frac{2}{5}[/tex] by [tex]\frac{1}{9}[/tex].

[tex]\frac{2}{5}[/tex] ÷[tex]\frac{1}{9}[/tex]

Let us convert division sign in multiplication and flip the second fraction, we get

[tex]\frac{2}{5} \times \frac{9}{1}[/tex]

= [tex]\frac{18}{5}[/tex]

= 3.6

Therefore, her battery will last in 3.6 hours.

Answer:

3.6 hours

Step-by-step explanation: