Respuesta :

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[tex]f(x)=-3x^2-4\\\\f(2)=-3(2^2)-4=-3(4)-4=-12-4=-16\neq32\\\\g(x)=4(x+3)^2-68\\\\g(2)=4(2+3)^2-68=4(5)^2-68=4(25)-68=100-68=32\ :)\\\\h(x)=3x\\\\h(2)=3(2)=6\neq32\\\\j(x)=2x-62\\\\j(2)=2(2)-62=4-62=-58\neq32\\\\Answer:\ \boxed{g(x)=4(x+3)^2-68}[/tex]

The function in which In which  x = 2 mapped to 32 is: g(x) = 4(x+3)² - 68 (Option B).

What is a mapped function?

Two-dimensional patterns are applied to surfaces using mapping functions.

Each model specifies a unique way for converting a three-dimensional point of intersection into a two-dimensional u-v pair known as texturing parameters.

Solution to the mapped function is?

f(x) = -3x² - 4

f(2) = -3(2²) -4

= -3(4)

= -12 -4

= -16 ≠ 32

g(x) = 4(x+3)² -68

g(2) = 4(2+3)² -68

=4(5)² - 68

= 4(25) - 68

= 100 -68

= 32

h(x) = 3x

h (2) = 3(2)

= 6 ≠ 32

j (x) = 2x - 62

j(2) = 2(2) - 62

= 4 - 62

= -58 ≠ 32

Hence, it is correct to state that the function in which In which  x = 2 mapped to 32 is: g(x) = 4(x+3)² - 68

Learn more about mapped functions at;
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