m∠GAH = 62° m∠ADB = 148° Find the m∠AFD.

if GAH = 62 then HAD = 118
because
GAH + HAD = 180 straight line
62+ HAD = 180
subtract 62 from each side
hAD = 118
FAD = 62
FAD + HAD = 180 it is a straight line
FAD +118 = 180
ADF + adb = 180 forms a straight line
ADF + 148 = 180
ADF = 32
A triangle = 180 degree
AFD + ADF + FAD = 180
AFD + 32+62 =180
AFD +94=180
AFD = 86