Respuesta :

We need to find, how many 1/3s are in 1 2/3 the hexagon represents 1 whole.

In order to find that value, we need to divide 1 2/3 by 1/3.

Let us first convert 1 2/3 into improper fraction first.

1 2/3 = (1*3+2)/3 = 5/3.

Therefore,

5/3 ÷ 1/3.

Changing division sign into multiplication and flipping the second fraction, we get

5/3 × 3/1

3's cross out from top and bottom, we get

= 5.

Therefore, there are 5 times of 1/3s in 1 2/3.

MrRoyal

The question is an illustration of fraction divisions .

There are 5 [tex]\frac{1}{3}s[/tex]  in [tex]1\frac{2}{3}[/tex]

The numbers are given as:

[tex]\mathbf{n_1 = \frac 13}[/tex]

[tex]\mathbf{n_2 = 1\frac 23}[/tex]

To get the number of 1/3s in 1 2/3, we simply divide 1 2/3 by 1/3.

So, we have:

[tex]\mathbf{n = n_2 \div n_1}[/tex]

This gives

[tex]\mathbf{n = 1\frac 23 \div \frac 13}[/tex]

Express as improper fractions

[tex]\mathbf{n = \frac 53 \div \frac 13}[/tex]

Express as products

[tex]\mathbf{n = \frac 53 \times \frac 31}[/tex]

[tex]\mathbf{n = 5}[/tex]

Hence, there are 5 [tex]\frac{1}{3}s[/tex]  in [tex]1\frac{2}{3}[/tex]

Read more about fraction divisions at:

https://brainly.com/question/17205173

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