So, we have 2 canoes with teams. They are both at a constant speed of 6mph, but one of them is 2mi ahead.
Assuming [tex]d = distance[/tex] and [tex]t = time[/tex],we express that as:
Team A = [tex]\frac{6d}{t}+2[/tex]
Team B = [tex]\frac{6d}{t}[/tex]
Because of those 2 extra miles and both canoes travelling at the same constant speed, they will never reach one another, like you correctly answered below.
