[tex]y=2x^2-4x+3[/tex]
[tex]y=4x-5[/tex]
both equation having y on the left side
So we can equate the right side of the equation
[tex]2x^2-4x+3 = 4x-5[/tex]
Subtract 4x on both sides
[tex]2x^2-8x+3 = -5[/tex]
Add 5 on both sides
[tex]2x^2-8x+8 = 0[/tex]
Now we solve for x
Divide the whole equation by 2
[tex]x^2-4x+4 = 0[/tex]
(x-2)(x-2)=0
(x-2)^2 =0
So x= 2
Now we find out y when x=2
y=4x-5
y= 4(2) -5
y = 8 -5 = 3
So solution is x=2 and y = 3
(2,3)
