Answer: The perimeter of the large triangle is 88 cm.
Explanation:
It is given that the ratio of corresponding sides of two similar figures is 3:8. The sides of the smaller triangle are 8 centimeters, 11 centimeters, and 14 centimeters long.
If the sides are is in the ratio of 3:8 then their perimeter is als in the ratio of 3:8.
The perimeter of small triangle is,
[tex]S_S=8+11+14=33[/tex]
The ratio of the small and large triangle is 3:8, Let [tex]S_L[/tex] is the perimeter of large triangle.
[tex]\frac{S_S}{S_L} =\frac{3}{8}[/tex]
[tex]\frac{33}{S_L} =\frac{3}{8}[/tex]
[tex]33\times \frac{8}{3}=S_L[/tex]
[tex]88=S_L[/tex]
Therefore the perimeter of the large triangle is 88 cm.
