m = mass of the car = 1800 kg
g = acceleration due to gravity = 9.8 m/s²
[tex]F_{g}[/tex] = force of gravity on the car
force of gravity on the car is given as
[tex]F_{g}[/tex] = mg
inserting the values
[tex]F_{g}[/tex] = (1800) (9.8) = 17640 N
[tex]f_{s}[/tex] = static frictional force acting on the car
from the force diagram of the car , the static frictional force is opposite to the parallel component of force of gravity on the car . hence static frictional force mus balance the component of force of gravity parallel to incline surface.
hence
[tex]f_{s}[/tex] = [tex]F_{g}[/tex] Sin7
[tex]f_{s}[/tex] = (17640) Sin7
[tex]f_{s}[/tex] = 2149.8 N
