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Here's how you would solve it with elimination:

-2x + 3y = 7

5x + 8y = -2

Multiply first equation by 5 and the second one by 2:

-10x + 15y = 35

10x + 16y = -4

Add the two equations:

-10x + 15y = 35

+

10x + 16y = -4

------------------------

31y = 31

y = 1

Plug this back into one of the original equation:

5x + 8y = -2

5x + 8(1) = -2

5x + 8 = -2

5x = -10

x = -2

Now you have your answer:

y = 1

x = -2

The solution to the system of linear equation by using the elimination method is x = -2 and y = 1

The elimination method involves equating two linear equations together in order to achieve the variables attached to the equations.

Given that:

−2x+3y =  7       ----- (1)

 5x+8y = −2     ------ (2)

We will look for a value that we can use to multiply both equations where one variable will be eliminated.

Let multiply equation (1) to by 5 and equation (2) by 2, we have:

  -10x + 15y = 35

+

   10x  + 16y = -4    

             31y = 31    

y = 31/31

y = 1

From equation (1), let's replace y with (1);

-2x + 3(1) = 7

-2x + 3 = 7

-2x = 7 - 3

-2x = 4

x = - 4/2

x = -2

Therefore, the solution to the system of linear equation by using the elimination method is x = -2 and y = 1

Learn more about linear equations by elimination here:

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