Respuesta :

[tex]Given : \frac{\frac{4t^2 - 16}{8}}{\frac{t - 2}{6}}[/tex]

[tex]\implies \frac{6(4t^2 - 16)}{8(t - 2)}[/tex]

[tex]\implies \frac{3(4t^2 - 16)}{4(t - 2)}[/tex]

[tex]\implies \frac{12(t^2 - 4)}{4(t - 2)}[/tex]

[tex]\implies \frac{3(t^2 - 4)}{(t - 2)}[/tex]

[tex]\implies \frac{3(t + 2)(t - 2)}{(t - 2)}[/tex]

⇒ 3(t + 2)