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Dalam ruang 1 liter, gas metana (ch4) direaksikan dengan 6 mol uap air sesuai reaksi:ch4(
g. 2 h2o(
g. ←→ co2(
g. 4 h2(
g. kc =16/3bila pada keadaan setimbang diperoleh 4 mol gas hidrogen, berapa mol gas metana yang dibutuhkan untuk reaksi kesetimbangan tersebut?

Respuesta :

In the space of 1 liter, methane gas (ch4) is reacted with 6 moles of water vapor according to the reaction: if at equilibrium state is obtained 4 moles of hydrogen gas, how many moles of methane gas is needed for the equilibrium reaction?

the reaction is

CH4(g)  + 2H2O(g)  ----> CO2(g)   + 4H2 (g)

Kc = 16 / 3

Kc = [CO2] [H2]^4 / [CH4] [H2O]^2

given :

equilibrium concentration

[H2] = 4 moles

so equilibrium concentration of CO2 must be 1 mole

equilibrium concentration of H2O = 6 - 2 = 4

putting values

16 /3 =  [1] [4]^4 / [CH4] [4]^2

[CH4] = 0.333 moles

so moles of CH4 required = 1.33 moles

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