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Yuto left his house at 10 a.m. to go for a bike ride. By the time Yuto’s sister Riko left their house, Yuto was already 5.25 miles along the path they both took. If Yuto’s average speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, over what time period in minutes, t, starting from when Riko left the house, will Riko be behind her brother?

Riko will be behind Yuto when 0 ≤ t <
minutes.

Respuesta :

littlelyna2love

-- When Riko left the house, Yuto was 5.25 miles ahead of her.


-- From the time she left the house, she gained (0.35 - 0.25) = 0.1 mile on Yuto

every minute ... closing the gap at the rate of 0.1 mile per minute.


-- If she can keep it up, she'll close the gap in (5.25 / 0.1) = 52.5 minutes.


-- Riko is behind her brother when  0 ≤ t < 52.5 minutes .

The time period from when Riko left the house, that Riko be behind her brother is;

0 ≤ t < 52.5 minutes

Range inequality

We are told that by the time Yuto’s sister Riko left the house, Yuto was already 5.25 miles ahead of her.

  • Yuto’s average speed was given as 0.25 miles/minute and Riko’s average speed was 0.35 miles/minute

This means that from the time that riko left the house, speed she gained per minute on yuto is;(0.35 - 0.25) = 0.1 mile/min

At this rate of 0.1 mile/min, the time it will take her to close the gap is;

5.25miles / 0.1 mile/min = 52.5 minutes.

In conclusion, we can say that Riko is behind her brother when the range of time is;

0 ≤ t < 52.5 minutes .

Read more about Range inequality at; https://brainly.com/question/13634469

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