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A 6.0 kg object undergoes an acceleration of 2.0 m/s2 .

a. what is the magnitude of the net external force acting on it?

b. if this same force is applied to a 4.0 kg object, what acceleration is produced?

Respuesta :

A. Fnet=ma
6*2=12N of force acting on the object in the direction it is accelerating

B. Fnet=ma
4*2=8N of force action on the object in the direction it is accelerating
okpalawalter8

We have that the magnitude of the net external force and the acceleration is give as

  • F=12N
  • a=3m/s^2

From the question we are told

A 6.0 kg object undergoes an acceleration of 2.0 m/s2 .  

a. what is the magnitude of the net external force acting on it?  

b. if this same force is applied to a 4.0 kg object, what acceleration is produced

a

Generally the equation for the  magnitude of the net external force is mathematically given as

F=ma

F=6*2

F=12N

b

Generally the equation for the  acceleration  is mathematically given as

[tex]a=\frac{F}{m}\\\\a=12/4\\\\a=3m/s^2[/tex]

Therefore the magnitude of the net external force and the acceleration is give as

  • F=12N
  • a=3m/s^2

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