We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then (f - g)(x) = f(x) - g(x)
Given f(x) = [tex]\frac{2x + 6}{3x}[/tex] and g(x) = [tex]\frac{\sqrt{x} - 8}{3x}[/tex]
⇒ (f - g)(x) = f(x) - g(x)
⇒ [tex](f - g)(x) = \frac{2x + 6}{3x} - \frac{\sqrt{x} - 8}{3x} = \frac{2x + 6 - \sqrt{x} + 8}{3x}[/tex]
⇒ [tex](f - g)(x) = \frac{2x - \sqrt{x} + 14}{3x}[/tex]
First Option is the answer
