Respuesta :
The doubling the amount will change the gibbs free energy as it is an extensive property which depends upon the the amount of the substance
However as asked in question the DeltaG has unit of kcal /mol
So we have already defined the amount of substance to be one mole this means the value per mole will be same irrespective of the amount taken as we are reporting it for a fixed one mole of a substance
Hence answer is
-100 kcal/mol
The [tex]\Delta {\text{G}}[/tex] for the new reaction is [tex]\boxed{ - 10{\text{0 kcal/mol}}}[/tex] when the amount of enzyme is doubled.
Further explanation:
Properties are categorized into two types:
1. Intensive properties:
These properties depend on the nature of the substance and not on the size of the system. If the system is further divided into a number of subsystems, the values of intensive properties remain unchanged. Temperature, refractive index, molarity, concentration, pressure, and density are some of the examples of intensive properties.
2. Extensive properties:
These properties depend on the amount of the substance. These are additive in nature if a single system is divided into several subsystems. Mass, enthalpy, Gibbs free energy, volume, energy, size, weight, and length are some of the examples of extensive properties.
As [tex]{\Delta G}}[/tex] is an extensive property, it should depend on the amount or quantity of substance. So if the amount of enzyme is doubled, the change in Gibbs free energy should also increase accordingly. But we are provided with the value of [tex]{\Delta G}}[/tex] in terms of kcal/mol (-100 kcal/mol). It means it is the value of [tex]{\Delta G}}[/tex] for one mole and therefore the amount of substance becomes constant. Hence the value of [tex]{\Delta G}}[/tex] will not change on changing the concentration of enzyme.
So [tex]{\mathbf{\Delta G}}[/tex] for the new reaction is -100 kcal/mol when the amount of enzyme is doubled in the reaction.
Learn more:
1. Calculate [tex]\Delta {\text{H}}[/tex] for the reaction using Hess law: https://brainly.com/question/11293201
2. Find the enthalpy of dissociation of 1 mole of MgO: https://brainly.com/question/2416245
Answer details:
Grade: Senior school
Subject: Chemistry
Chapter: Thermodynamics
Keywords: Gibbs free energy, -100 kcal/mol, enzyme, doubled, intensive, extensive, amount of substance, nature of substance, unchanged, additive, new reaction, kcal/mol.
