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Which table contains the vertex of the graph represented by y=x^2-6x+4?

X. Y
-2 20
0 4
2 -4
4 -4


X. Y
-1 11
1. -1
3. -5
6. 4

X. Y
-3. 31
-1. 12
0. 4
2 12

X. Y
0 5
2 7
3. 5
5. 7

Respuesta :

vertex = (3,- 5 )

given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then

the x-coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = x² - 6x + 4 is in standard form

with a = 1, b = - 6 and c = 4, hence

[tex]x_{vertex}[/tex] = - [tex]\frac{-6}{2}[/tex] = 3

substitute this value into the equation for y- coordinate

y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5

vertex = (3, - 5 ) → second table




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