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The product of two integers is 112 . One number is four more then three times the other .
Which of the following equations could be used to find one of the numbers ?
A. 3x^2+4x=112
B. 4x^2+3=112
C. 4x^2+3x=112
D. 3x^2+4=112

Respuesta :

gmany

x, y - two integers

the product of two integers is 112

(1)      xy = 112

one number is four more then three times the other

(2)     y = 3x + 4             substitute it to (1)

x(3x + 4) = 112      use distributive property

(x)(3x) + (x)(4) = 112

3x² + 4x = 112

Answer: A. 3x^2+4x=112

vijayhalder031

The correct answers is Option (a) 3x^2+4x=112

How to solve the problem?

Let the two integers be x and y

the product of two integers is 112

That is x*y = 112

Now  one number is four more then three times the other

 y = 3x + 4    

Substitute the value to x*y = 112

x(3x+4)=112

= 3x^2+4x=112

Hence Option (A) is correct

Learn more about Integers here

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