Respuesta :

Answer : The moles of potassium chloride and oxygen produced can be 0.813 and 2.44 respectively.

Explanation : Given,

Mass of [tex]KClO_3[/tex] = 100.0 g

Molar mass of [tex]KClO_3[/tex] = 123 g/mole

The balanced chemical reaction will be,

[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]

First we have to calculate the moles of [tex]KClO_3[/tex].

[tex]\text{ Moles of }KClO_3=\frac{\text{ Mass of }KClO_3}{\text{ Molar mass of }KClO_3}=\frac{100.0g}{123g/mole}=0.813moles[/tex]

Now we have to calculate the moles of [tex]KCl[/tex] and [tex]O_2[/tex].

From the balanced chemical reaction we conclude that,

As, 2 mole of [tex]KClO_3[/tex] react to give 2 mole of [tex]KCl[/tex]

So, 0.813 mole of [tex]KClO_3[/tex] react to give 0.813 mole of [tex]KCl[/tex]

and,

As, 2 mole of [tex]KClO_3[/tex] react to give 3 mole of [tex]O_2[/tex]

So, 0.813 mole of [tex]KClO_3[/tex] react to give 3 × 0.813 = 2.44 mole of [tex]O_2[/tex]

Therefore, the moles of potassium chloride and oxygen produced can be 0.813 and 2.44 respectively.

pstnonsonjoku

From the stoichiometry of the reaction, 1.23 moles of oxygen and 0.82 moles of potassium chloride were produced.

We have the reaction equation of this reaction as; 2 KClO3----->2KCl + 3O2. The number of moles of  potassium chlorate is obtained from;

Number of moles = 100.0g/122.55 g/mol = 0.82 moles

For the number of moles of oxygen produced;

2 moles of potassium chlorate produces 3 moles of oxygen

0.82 moles of potassium chlorate produces 0.82 moles × 3 moles/2 moles

= 1.23 moles

For number of moles of potassium chloride produced;

2 moles of potassium chlorate produces 2 moles of potassium chloride

0.82 moles of potassium chlorate produces 0.82 moles × 2 moles/2 moles

= 0.82 moles

Learn more about stoichiometry: https://brainly.com/question/12978582

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