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Lori buys a $672 certificate of deposit (CD) that earns 7.1% interest that compounds monthly. How much will the CD be worth in 14 years?

Respuesta :

The formula is

A=p(1+r/n)^nt

A future value ?

P present value 672

R interest rate 0.071

N compounded monthly 12

T time 14 years

A=672×(1+0.071÷12)^(12×14)

A=1,810.45

Hope it helps!

Answer:

The CD will be worth $1810.44 in 14 years.

Step-by-step explanation:

This is a compound interest problem:

The compound interest formula is given by:

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this exercise, we have:

[tex]P = 672[/tex]

[tex]r = 0.071[/tex].

There are 12 months in a year, and so, 12 compoundings in a year. So [tex]n = 12[/tex].

We want to know the CD's worth in 14 years. So [tex]t = 14[/tex].

So

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

[tex]A = 672(1 + \frac{0.071}{12})^{12*14}[/tex]

[tex]A = 1810.44[/tex]

The CD will be worth $1810.44 in 14 years.