(-1/8 c+16)-(3/8+3c)=
= -1/8c + 16 - 3/8 - 3c
= (-1/8 c - 3c) + (16 - 3/8)
= (1/8 c - 24/8 c) + (128/8 - 3/8)
= - 23/8 c + 125/8
Answer:
[tex]-3.125c+15.625[/tex]
Step-by-step explanation:
We have the expression
[tex](-\frac{1}{8}c+16)-(\frac{3}{8}+3c )[/tex]
First we eliminate the parenthesis by multiplying the second parenthesis by the negative.
[tex]-\frac{1}{8}c+16-\frac{3}{8}-3c[/tex]
and now we put together similar terms, adding the terms that contain [tex]c[/tex]:
[tex](-\frac{1}{8}-3)c+16-\frac{3}{8}[/tex]
[tex](-\frac{1}{8}-\frac{3}{1})c+16-\frac{3}{8}[/tex]
[tex](\frac{(-1)(1)-(3)(8)}{8(1)})c+16-\frac{3}{8}[/tex]
[tex](\frac{(-1-24)}{8})c+16-\frac{3}{8}[/tex]
[tex]\frac{-25}{8}c+16-\frac{3}{8}[/tex]
and now we put together the independent quantities:
[tex]\frac{-25}{8}c+\frac{16}{1} -\frac{3}{8}[/tex]
[tex]\frac{-25}{8}c+\frac{16(8)-3(1)}{8}[/tex]
[tex]\frac{-25}{8}c+\frac{128-3}{8}[/tex]
[tex]\frac{-25}{8}c+\frac{125}{8}[/tex]
And if we convert the fractions to decimals we have:
[tex]-3.125c+15.625[/tex]
