we are given
[tex]f(d)=-0.6d^2+5.4d+0.8[/tex]
where
d is the horizontal distance the ball traveled in yards
f(d) is the height, in yards of the ball at d horizontal yards
Initial height:
For finding initial height , we can plug d=0
[tex]f(0)=-0.6(0)^2+5.4(0)+0.8[/tex]
[tex]f(0)=0.8[/tex]
So, initial height is 0.8 yard
Initial Velocity:
We can find derivative
[tex]f'(d)=-0.6\times 2d+5.4\times 1+0[/tex]
[tex]f'(d)=-1.2d+5.4+0[/tex]
now, we can plug d=0
[tex]f'(0)=-1.2(0)+5.4+0[/tex]
[tex]f'(0)=5.4[/tex]
so, initial velocity is 5.4 yard vertically / yard horizontally
Hence , option-B.......Answer