we are given
[tex]f(s)=-0.0009s^2+0.699s+12[/tex]
where
s represents the average speed of the car in miles per hour
For maximum fuel economy , we will have to find derivative of f(s)
and then we set it to 0
after that we can solve for s
[tex]f'(s)=-0.0009\times 2s+0.699+0[/tex]
[tex]f'(s)=-0.0018s+0.699[/tex]
now, we can set it to 0
and then we can solve for s
[tex]f'(s)=-0.0018s+0.699=0[/tex]
[tex]-0.0018s=-0.699[/tex]
[tex]s=\frac{0.699}{0.0018}[/tex]
[tex]s=388.333[/tex]mph....................Answer