parallel lines have the same slope
3x+2y =1
solve for y to find the slope
subtract 3x
2y = -3x+1
divide by 2
y = -2/3 x+1/2
slope is -2/3
point slope form is
y-y1 = m(x-x1)
y-15 = -2/3 (x--6)
y-15 = -2/3 (x+6)
distribute
y-15=-2/3x-4
add 15 to each side
y = -2/3 x +11
this is in slope intercept form
10. passes through (5, 2), perpendicular to the graph of x + 2y = 8
perpendicular lines have negative reciprocal slopes
x+2y=8
subtract x
2y = -x+8
divide by 2
y = -1/2 x +4
-1/2 becomes 2
the new slope is 2
point slope form is
y-y1 = m(x-x1)
y--2 = 2(x-5)
y+2 = 2x-10
subtract 2 from each side
y = 2x-12
this is in slope intercept form
