contestada

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)?

y + 3 = −4(x + 4)
y + 3 = –(x + 4)
y + 3 = (x + 4)
y + 3 = 4(x + 4)

What is the equation in pointslope form of the line that is perpendicular to the given line and passes through the point 4 3 y 3 4x 4 y 3 x 4 y 3 x 4 y 3 4x 4 class=

Respuesta :

wegnerkolmp2741o

(0,-3) (-1,1)

slope = (y2-y1)/(x2-x1)

m =(1--3)/(-1-0)

m=(1+3)/-1

m=4/-1  = -4


perpendicular lines have negative reciprocal slope so -4 becomes 1/4

point slope form

y-y1=1/4(x-x1)

y--3 = 1/4(x--4)

y+3 = 1/4 (x+4)


Choice C

Otras preguntas