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TheGreatWulfbite

These two linear equations are perpendicular, because 3y=4x+15 has a slope of [tex]\frac{4}{3}[/tex] and 9x+12y=12 has a slope of - [tex]\frac{3}{4}[/tex] , and since those two fractions have exact opposite slopes (flip the denominator and numerator and multiply by -1), they are perpendicular.

MrGumby

Answer:

These two lines are perpendicular.

Step-by-step explanations:

In order to find this, we need to compare slopes. If they are the same it is parallel, if it is opposite and reciprocal then it is perpendicular, and if it is neither of those things then it is neither. To find the slopes, we need to solve both equations for y.

3y = 4x + 15

y = 4/3x + 5

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9x + 12y = 12

12y = -9x + 12

y = -3/4x + 1

The slopes of 4/3 and -3/4 are opposite and reciprocal. Therefore it is perpendicular.


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