The solution set of x^2-2x-8=0

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KSGIR KSGIR · Answer 1 · 2018-11-09T02:52:35+01:00

x2−2x−8=0

Factor left side of equation.

(x+2)(x−4)=0

Set factors equal to 0.

x+2=0 or x−4=0

x=−2 or x=4

Answer:

x=−2 or x=4

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Abdulazeez10 Abdulazeez10 · Answer 2 · 2021-11-04T10:21:23+01:00

The solution set of the given quadratic equation is (4, -2). The correct option is F. (4, -2)

From the question

We are to determine the solution set of the quadratic equation x² -2x -8 =0

The solution set of the quadratic equation x² -2x -8 =0 can be determined as shown below

x² -2x -8 =0

x² -4x+2x -8 =0

Then,

Factorizing, we get

x (x -4) +2(x -4) = 0

This becomes

(x +2)(x -4) = 0

∴ x +2 =0 OR x -4 =0

x = 0 -2 OR x = 0 +4

x = -2 OR x = 4

∴ The solution set is (4, -2)

Hence, the solution set of the given quadratic equation is (4, -2). The correct option is F. (4, -2)

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