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nap14hockey

So, we will be using point-slope form to construct this equation.


Point-slope form's general formula is as follows:

[tex]Y-Y_1=m(X-X_1)[/tex]

M is the slope,

Y₁ is the Y-coordinate of the point

X₁ is the X- coordinate of the point.


So, our slope is 3 (since the equation is given in slope-intercept form)

Our Y₁ is 7 and out X₁ is 4


So, now we just plug our numbers into the equation.

[tex]Y-7 = 3(X-4)[/tex]


There's your equation.


Hope this helps!

adioabiola

The equation of the line passing through the point (4,7) and parallel to the line: y = 3x + 6 is;

y= 3x - 5

We must first remember that the slope of parallel lines are equal.

In essence, If line 1 is parallel to line 2,

  • Then; m1 = m2.

Since the equation y = 3x + 6 already takes the slope-intercept form; y = mx +c.

  • The slope of the line, m1 = 3.

  • Consequently, m1 = 3 = m2.

The slope of the parallel line, m2 = 3 and the line passes through the point (4,7).

Therefore;

  • 3 = (y - 7)/(x-4)

By cross product;

  • 3x - 12 = y - 7

y = 3x - 5

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