Let x be the speed of eastbound train
The eastbound train travels 20 miles per hour slower than the westbound train.
so the speed of westbound train is x + 20
Distance = speed * time
Time = 4 hours
Distance traveled by each bound train = 4x
Distance traveled by westbound train = 4(x+20)
Two trains are 800 miles apart
4x + 4(x+20) = 800
4x + 4x + 80 = 800
8x + 80 = 800
Subtract 80 from both sides
8x = 720
Divide both sides by 8
x = 90
The speed of east bound train is 90 miles per hour
Answer:
90 mph
Step-by-step explanation:
Let the speed of the westbound train (A) be x mph; and
the speed of the eastbound (B) train be (x-20) mph.
We know that distance = speed x time
so distance traveled by A = 4x; and
the distance traveled by B = 4 (x - 20) = 4x - 80.
Adding these distances up to get:
4x + (4x - 80) = 800
4x + 4x = 800 - 80
8x = 720
x = 720/8
x = 90
Therefore, the rate at which the eastbound train travels is 90 mph.
