A car passes a landmark on a highway traveling at a constant rate of 45 kilometers per hour.
Let t be the time taken by second car
So t+1 is the time taken by first car
Distance = speed * time
Distance traveled by first car = 45 * (t+1)
second car passes the same landmark traveling in the same direction at 65 kilometers per hour
Distance traveled by second car = 65 * (t)
When second car overtakes the first car then their distance are same
65 t = 45(t+1)
65t = 45t + 45
Subtract 45 t from both sides
20t = 45
Divide both sides by 20
so [tex]t = \frac{45}{20}=\frac{9}{4}=2.25[/tex]
It took 2.25 hours for the second car to overtake first car
Answer:
2 hours 15 mins
Step-by-step explanation:
We know,
the speed of car 1 = 45 kilometers per hour; and
the speed of car 2 = 65 kilometers per hour
Assuming the time for the 2nd car to catch the 1st one to be t, we can write the distance equation:
[tex]65t=45t+45[/tex]
[tex]65t-45t=45[/tex]
[tex]20t=45[/tex]
[tex]t=45/20[/tex]
[tex]t=2.25[/tex]
2.25 hours = 2 hours + (0.25 * 60) min = 2 hours 15 mins
Therefore, it takes 2 hours 15 mins for the second car to overtake first car after it passes the landmark.
