Let's assume
boiling point is y
altitude is x
we are given
This relationship between altitude and boiling point is linear
At an altitude of 1000 feet, water boils at 210°F
so, first point is (1000,210)
so, x1=1000 , y1=210
At an altitude of 3000 feet, water boils at 206°F
so, second point is (3000,206)
so, x2=3000,y2=206
now, we can find slope
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
now, we can plug values
[tex]m=\frac{206-210}{3000-1000}[/tex]
[tex]m=-\frac{1}{500}[/tex]
now, we can use point slope form of line
[tex]y-y_1=m(x-x_1)[/tex]
so, we can plug it
[tex]y-210=-\frac{1}{500}(x-1000)[/tex]
so, point slope form of line is
[tex]y-210=-\frac{1}{500}(x-1000)[/tex]
now, we can plug x=8000
and then we can solve for y
[tex]y-210=-\frac{1}{500}(8000-1000)[/tex]
[tex]y=196[/tex]
So,
the boiling point of water at an altitude of 8000 feet is 196°F..........Answer
