Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each horizontal foot. The hill on 16th Avenue rises 1 vertical foot for every 3 horizontal feet.

Which hill will be more difficult for Steve to run up? Explain your reasoning.

1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.

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santiagoposso22 santiagoposso22 · Answer 2 · 2019-09-21T01:16:37+02:00

Answer:

The first Avenue will be more difficult for Steve to run up.

Step-by-step explanation:

Before to get started, please take a look at the attached sketch below.

Take in account that slope is a number that describes the steepness of a line. It can be computed through the ratio of the vertical change to the horizontal change.

According to this, the slope of the first avenue is 3/1 and the slope of the 16th avenue is 1/3. Therefore, the first avenue inclination is greater than 16 th avenue. This means that the first avenue requires more effort to be run up.

Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each horizontal foot. The hill on 16th Avenue rises 1 vertical foot for every 3 horizontal feet. Which hill will be more difficult for Steve to run up? Explain your reasoning.

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Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each horizontal foot. The hill on 16th Avenue rises 1 vertical foot for every 3 horizontal feet.

Which hill will be more difficult for Steve to run up? Explain your reasoning.