Answer:
[tex]\frac{y+1}{y-1}[/tex]
Step-by-step explanation:
[tex]\frac{1+\frac{1}{y}}{1-\frac{1}{y}}[/tex]
First we simplify the numerator
[tex]1+\frac{1}{y}[/tex], make the denominators same
[tex]\frac{1*y}{1*y}+\frac{1}{y}[/tex]
[tex]\frac{y+1}{y}[/tex]
now we simplify the denominator
[tex]1-\frac{1}{y}[/tex], make the denominators same
[tex]\frac{1*y}{1*y}-\frac{1}{y}[/tex]
[tex]\frac{y-1}{y}[/tex]
[tex]\frac{\frac{y+1}{y}}{\frac{y-1}{y}}[/tex]
both top and bottom have same denominator y so we cancel it out
[tex]\frac{y+1}{y-1}[/tex]
