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Solve: Find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times the smaller number.

Respuesta :

carlosego

The answer is: 29 and 31.

1. Let's call the smaller odd number: [tex]x[/tex].

2. Let's call the larger odd number: [tex]x+2[/tex]

3. Based on the information given in the problem, the sum of the larger number ([tex]x+2[/tex]) and twice the smaller number ([tex]2x[/tex]) is 27 less than four times the smaller number ([tex]4x-27[/tex]).

4. Then, you can write the following expression and solve for [tex]x[/tex] to find the smaller number:

[tex]x+2+2x=4x-27\\2+27=4x-3x\\x=29[/tex]

5. Therefore, the larger number is:

[tex]29+2=31[/tex]

alinakincsem

Answer:

Smaller number = 29 and larger number = 31.

Step-by-step explanation:

Let the two consecutive odd numbers be x (smaller number) and x+2 (larger number).

We know that the sum of the larger number (x+2) and twice the smaller number (2x) is equal to 27 less than four times the smaller number (= 4x - 27). So we can write it as:

[tex](x+2)+2x=4x-27[/tex]

Solving for [tex]x[/tex] to get:

[tex]x+2+2x= 4x-27[/tex]

[tex]3x+2=4x-27[/tex]

[tex]x=29[/tex]

and [tex](x+2)= 29+2=31[/tex]

Therefore the smaller number = 29 and larger number = 31.

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