Respuesta :

gmany

The point-slope form

[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (-1, -10) and (5, 2). Substitute:

[tex]m=\dfrac{2-(-10)}{5-(-1)}=\dfrac{12}{6}=2\\\\y-(-10)=2(x-(-1))\\\\\boxed{y+10=2(x+1)}[/tex]

harmonyhope12

If your equation starts off as y-2= then this your Answer: y-2=2(x-5)

Step-by-step explanation: the general point-slope form is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point of the line.

Let's find the slope between(5,2) and (-1,-10)

Slope= 2-(-10)/5-(-1)

=12/6

=2

The incomplete equation starts off with y-2, so we need to use the point (5,2):

Y-2=2(x-5)

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