Ethan rolls a 6-sided number cube. What is the probability that he gets a number less than 3?

We have been given that Ethan rolls a 6-sided number cube. Then, the sample space is S={1, 2, 3, 4, 5, 6}
n(S) = 6
Let E be the event of getting a number less than 3.
Then, E = {1, 2}
n(E) = 2
Probability of an event is given by [tex]\frac{n(E)}{n(S)}[/tex]
[tex]= \frac{2}{6}[/tex]
[tex]= \frac{1}{3}[/tex]
Hence, the probability that Ethan gets a number less than 3 is [tex]\frac{1}{3}[/tex].
The probability that Ethan gets a number less than 3 is; C: 1/3
We are told that Ethan rolls a 6-sided number cube. Thus, the sample space is; S = {1, 2, 3, 4, 5, 6}
Thus; n(S) = 6
Let E be the event of getting a number less than 3.
Then, E = {1, 2} and n(E) = 2
Then, probability of the event is given by;
P(a number less than 3) = n(E)/n(S) = 2/6 = 1/3
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