Barium chloride reacts with silver nitrate to form a precipitate of silver chloride along with soluble solution of barium nitrate. The equation is as follows:
BaCl2(aq) + AgNO3(aq) → AgCl(s) + Ba(NO3)2(aq)
Lets balance the equation:
Reactants Products
# Ba atoms = 1 #Ba atoms = 1
# Cl atoms = 2 # Cl atoms = 1
# Ag atoms = 1 # Ag atoms = 1
# NO3- group = 1 # NO3- group = 2
Thus the balanced equation needs to be balanced w.r.t Cl and NO3-
BaCl2(aq) + 2AgNO3(aq) → 2AgCl(s) + Ba(NO3)2(aq)
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