Respuesta :
This looks like: [tex]\frac{x^2+7x-30}{x+10}[/tex]
To solve this problem, you'll want to use the AC method to factor x^2+7x-30.
After factoring your expression will look like this:
[tex]\frac{(x-3)(x+10)}{x+10}[/tex]
Cancel out the x+10 because they are common factors, so you are just left with the simple x-3.
Answer is:
x - 3
Answer:
[tex](x-3)[/tex]
Step-by-step explanation:
[tex]\frac{x^2+7x-30}{x+10}[/tex]
To divide it, we need to factor the numerator
lets factor [tex]x^2+7x-30[/tex]
product is [tex]-30[/tex] and sum is 7
we need to find out two factors whose product is [tex]-30[/tex] and sum is 7
[tex]10 \cdot (-3)= -30[/tex]
[tex]10-3=7[/tex]
[tex]x^2+7x-30[/tex]
[tex](x+10)(x-3)[/tex]
Replace it in the denominator
[tex]\frac{x^2+7x-30}{x+10}[/tex]
[tex]\frac{(x+10)(x-3)}{x+10}[/tex]
cancel out x+10
[tex](x-3)[/tex]
